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what will be the output of the following program segment: int x=3, y = 17; cout << x/y <<y/x << (y/x) + (x % y);

Question

What will be the output of the following program segment:

int x = 3, y = 17;  
cout &lt;&lt; x / y &lt;&lt; y / x &lt;&lt; (y / x) + (x % y);
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Solution

The output of the program segment will be 05.

Here's the step by step explanation:

  1. x/y will be 0 because both x and y are integers and integer division of 3/17 gives 0 as 3 is less than 17.

  2. y/x will be 5 because both y and x are integers and integer division of 17/3 gives 5 as the quotient.

  3. (y/x) + (x % y) will be 5 + 3 = 8. Here, y/x is 5 as explained above and x % y is 3 because the remainder of 3/17 is 3 as 3 is less than 17.

So, the output will be 0 (from x/y), 5 (from y/x), and 8 (from (y/x) + (x % y)). But since these are all printed together without any spaces or other separators, they will appear as 058.

This problem has been solved

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