Calculate the overall order of the reaction whose rate law expression was predicted as :Rate =k[NO]3/2 [O ]1/2
Question
Calculate the overall order of the reaction whose rate law expression was predicted as:
Solution
The overall order of a reaction is determined by adding up the exponents in the rate law expression.
In the given rate law expression: Rate = k[NO]^(3/2)[O]^(1/2)
The order with respect to [NO] is 3/2 and the order with respect to [O] is 1/2.
To find the overall order of the reaction, add these two values together:
Overall order = (3/2) + (1/2) = 2
So, the overall order of the reaction is 2.
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