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De Broglie wavelength was found to be equal toa.Compton wavelengthb.Photon wavelengthc.Bragg wavelength

Question

De Broglie wavelength was found to be equal to:

  • a. Compton wavelength
  • b. Photon wavelength
  • c. Bragg wavelength
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Solution

The de Broglie wavelength is a term used in quantum mechanics to describe the wave properties of particles such as electrons. It is named after the physicist Louis de Broglie. The de Broglie wavelength is given by the equation λ = h/p, where h is Planck's constant and p is the momentum of the particle.

a. Compton wavelength: The Compton wavelength is a quantum mechanical property of a particle. It is defined as the wavelength of a photon whose energy is the same as the rest-mass energy of the particle. The Compton wavelength of a particle is given by λ = h/mc, where h is Planck's constant, m is the rest mass of the particle, and c is the speed of light. The de Broglie wavelength is not necessarily equal to the Compton wavelength.

b. Photon wavelength: The wavelength of a photon is related to its energy by the equation λ = h/p, where h is Planck's constant and p is the momentum of the photon. This is the same equation as the de Broglie wavelength, so in this sense, the de Broglie wavelength of a particle can be thought of as equivalent to the wavelength of a photon with the same momentum.

c. Bragg wavelength: The Bragg wavelength refers to the wavelength of light that is diffracted by a crystal lattice. The Bragg wavelength is given by the equation λ = 2d sin θ, where d is the spacing between the lattice planes and θ is the angle of incidence of the light. The de Broglie wavelength is not necessarily equal to the Bragg wavelength.

In conclusion, the de Broglie wavelength can be thought of as equivalent to the photon wavelength in the sense that they are both given by the equation λ = h/p. However, it is not necessarily equal to the Compton wavelength or the Bragg wavelength.

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