Determine the unit of ‘c, given; x = a + bt + ct2,  x is in metres and t in second. a.m/s2b.m2/sc.kgm/sd.m/s

To determine the unit of 'c' in the equation x = a + bt + ct^2, we need to analyze the units of each term in the equation.

Given that x is in meters and t is in seconds, we can determine the units of 'a', 'b', and 'c' by comparing the units on both sides of the equation.

The first term, 'a', is added to x. Since x is in meters, 'a' must also be in meters.

The second term, 'bt', is multiplied by t. Since t is in seconds, 'b' must have units of meters per second (m/s) to ensure that the product has units of meters.

Now, let's focus on the third term, 'ct^2'. Since t is in seconds, 'c' must have units of meters per second squared (m/s^2) to ensure that the product has units of meters.

Therefore, the unit of 'c' in the equation x = a + bt + ct^2 is meters per second squared (m/s^2).