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decreasing boiling pointCH3COOH, C2H5OH, CH3NH2, CH3OCH3------------------------------------------------------------------------------------

Question

Decreasing boiling point

Compounds:

  • CH₃COOH
  • C₂H₅OH
  • CH₃NH₂
  • CH₃OCH₃

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Solution

The boiling point of a substance is determined by the type of intermolecular forces acting between its molecules. The stronger the intermolecular forces, the higher the boiling point.

  1. CH3COOH (Acetic Acid): This molecule can form hydrogen bonds, which are the strongest type of dipole-dipole interaction. This is because it has a hydrogen atom attached to an oxygen atom (a highly electronegative element). Therefore, it has the highest boiling point among the four.

  2. C2H5OH (Ethanol): This molecule can also form hydrogen bonds because it has a hydrogen atom attached to an oxygen atom. However, it has a smaller molecular size compared to acetic acid, which means less surface area for intermolecular interaction, resulting in a slightly lower boiling point.

  3. CH3NH2 (Methylamine): This molecule can form hydrogen bonds as well, but nitrogen is less electronegative than oxygen, making the hydrogen bonds weaker than those in acetic acid and ethanol. Therefore, it has a lower boiling point.

  4. CH3OCH3 (Dimethyl Ether): This molecule can only form dipole-dipole interactions and London dispersion forces, which are weaker than hydrogen bonds. Therefore, it has the lowest boiling point.

So, the decreasing order of boiling points is: CH3COOH > C2H5OH > CH3NH2 > CH3OCH3.

This problem has been solved

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