Find the angle of intersection of the plane y-3x-2z=-5 with the plane 4x-3y-2z=0 . Answer in radians: and in degrees:
Question
Solution 1
To find the angle of intersection between two planes, we first need to find the normal vectors of the planes. The normal vector of a plane ax + by + cz = d is (a, b, c).
- For the plane y - 3x - 2z = -5, the normal vector is (-3, 1, -2).
- For the plane 4x - 3y - 2z = 0, the normal vector is (4, Knowee AI is a powerful AI-powered study tool designed to help you to solve study problem.
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