Calculate the angle (in degree) between the vectors a and b, where i, j and k are unit vectors in the x-, y- and z-directionsa = 2i + 3j - kb = -4i + j + 5k
Question
Calculate the angle (in degree) between the vectors
a and b, where i, j and k are unit vectors in the x-, y- and z-directions
a = 2i + 3j - k
b = -4i + j + 5k
Solution
The angle between two vectors can be calculated using the dot product formula:
a.b = |a||b|cosθ
where:
- a.b is the dot product of vectors a and b
- |a| and |b| are the magnitudes of vectors a and b
- θ is the angle between a and b
First, let's calculate the dot product of vectors a and b:
a.b = (2*-4) + (31) + (-15) = -8 + 3 - 5 = -10
Next, let's calculate the magnitudes of vectors a and b:
|a| = sqrt((2^2) + (3^2) + (-1^2)) = sqrt(4 + 9 + 1) = sqrt(14)
|b| = sqrt((-4^2) + (1^2) + (5^2)) = sqrt(16 + 1 + 25) = sqrt(42)
Now, we can substitute these values into the dot product formula and solve for θ:
-10 = sqrt(14)*sqrt(42)*cosθ
cosθ = -10 / (sqrt(14)*sqrt(42))
θ = cos^-1(-10 / (sqrt(14)*sqrt(42)))
Using a calculator, we find that θ ≈ 120.52 degrees.
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