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Calculate the angle (in degree) between the vectors a and b, where i, j and k are unit vectors in the x-, y- and z-directionsa = 2i + 3j - kb = -4i + j + 5k

Question

Calculate the angle (in degree) between the vectors

a and b, where i, j and k are unit vectors in the x-, y- and z-directions

a = 2i + 3j - k
b = -4i + j + 5k

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Solution

The angle between two vectors can be calculated using the dot product formula:

a.b = |a||b|cosθ

where:

  • a.b is the dot product of vectors a and b
  • |a| and |b| are the magnitudes of vectors a and b
  • θ is the angle between a and b

First, let's calculate the dot product of vectors a and b:

a.b = (2*-4) + (31) + (-15) = -8 + 3 - 5 = -10

Next, let's calculate the magnitudes of vectors a and b:

|a| = sqrt((2^2) + (3^2) + (-1^2)) = sqrt(4 + 9 + 1) = sqrt(14)

|b| = sqrt((-4^2) + (1^2) + (5^2)) = sqrt(16 + 1 + 25) = sqrt(42)

Now, we can substitute these values into the dot product formula and solve for θ:

-10 = sqrt(14)*sqrt(42)*cosθ

cosθ = -10 / (sqrt(14)*sqrt(42))

θ = cos^-1(-10 / (sqrt(14)*sqrt(42)))

Using a calculator, we find that θ ≈ 120.52 degrees.

This problem has been solved

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