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: If a molecule of DNA consists of 22 percent cytosine, what percentage of the molecule isadenine

Question

If a molecule of DNA consists of 22 percent cytosine, what percentage of the molecule is adenine?

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Solution

In a DNA molecule, the amount of adenine (A) is always equal to the amount of thymine (T), and the amount of cytosine (C) is always equal to the amount of guanine (G). This is known as Chargaff's rule.

Given that the DNA molecule consists of 22 percent cytosine, it also consists of 22 percent guanine (because the amount of cytosine and guanine are always equal).

So, the total percentage of the DNA molecule that is either cytosine or guanine is 22% + 22% = 44%.

Since a DNA molecule is 100% in total, the combined percentage of adenine and thymine is 100% - 44% = 56%.

And because the amount of adenine and thymine are equal, the percentage of the DNA molecule that is adenine is 56% / 2 = 28%.

So, 28% of the DNA molecule is adenine.

This problem has been solved

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