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Find the number of terms and the sum of the terms of the arithmetic progressions 32,28,….4a.14 : 252b.8 : 144c.15 : 270d.7 : 126

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Find the number of terms and the sum of the terms of the arithmetic progressions 32,28,….4a.14 : 252b.8 : 144c.15 : 270d.7 : 126
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Solution 1

Sure, let's solve this step by step:

a. 32, 28, …, 4

The common difference (d) here is 28 - 32 = -4. The first term (a) is 32 and the last term (l) is 4.

The number of terms (n) in an arithmetic progression can be found using the formula: n = [(l - a) / d] + 1

So, n = [(4 - 32) / -4] + 1 = 8

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Knowee AI  is a powerful AI-powered study tool designed to help you to solve study problem.
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