Solve the equation 3, x, squared, plus, 2, x, minus, 10, equals, 03x 2 +2x−10=0 to the nearest tenth.

The given equation is a quadratic equation in the form ax^2 + bx + c = 0. The equation is 3x^2 + 2x - 10 = 0.

Step 1: Identify the coefficients a, b, and c in the equation. Here, a = 3, b = 2, and c = -10.

Step 2: Use the quadratic formula to solve for x. The quadratic formula is x = [-b ± sqrt(b^2 - 4ac)] / (2a).

Step 3: Substitute the values of a, b, and c into the formula.

x = [-2 ± sqrt((2)^2 - 43(-10))] / (23) x = [-2 ± sqrt(4 + 120)] / 6 x = [-2 ± sqrt(124)] / 6 x = [-2 ± 2sqrt(31)] / 6 x = -1/3 ± sqrt(31)/3

So, the solutions to the equation are x = -1/3 + sqrt(31)/3 and x = -1/3 - sqrt(31)/3.

To the nearest tenth, these are approximately x = 1.5 and x = -2.2.