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If a = 0.24 & b = 1.76, then compute the following expression.a4 + 4ab3 + 6a2b2 + 4ab3 + b4

Question

If a = 0.24 & b = 1.76, then compute the following expression.

a4+4ab3+6a2b2+4ab3+b4 a^4 + 4ab^3 + 6a^2b^2 + 4ab^3 + b^4

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Solution

Sure, let's break it down:

  1. Compute a^4: a^4 = (0.24)^4 = 0.0033

  2. Compute 4ab^3: 4ab^3 = 4 * 0.24 * (1.76)^3 = 3.7687

  3. Compute 6a^2b^2: 6a^2b^2 = 6 * (0.24)^2 * (1.76)^2 = 1.5094

  4. Compute 4ab^3 again (since it's repeated in the expression): 4ab^3 = 3.7687 (as computed above)

  5. Compute b^4: b^4 = (1.76)^4 = 9.6030

  6. Add all the computed values together: 0.0033 + 3.7687 + 1.5094 + 3.7687 + 9.6030 = 18.6531

So, a^4 + 4ab^3 + 6a^2b^2 + 4ab^3 + b^4 = 18.6531

This problem has been solved

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