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x P(X = x)3 .046 .629 ?12 .21Look at the relative frequency table above. What is P(X = 9) assuming the table represents all possible outcomes?

Question

x

P(X = x)
3
.046
.629
?12
.21
Look at the relative frequency table above. What is P(X = 9) assuming the table represents all possible outcomes?

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Solution

The table provided does not include a value for P(X = 9). However, since the table represents all possible outcomes, the probabilities should add up to 1.

Given the probabilities for X = 3 and X = 12, we can calculate the missing probability:

P(X = 3) = 0.046 P(X = 12) = 0.21

Adding these together gives 0.046 + 0.21 = 0.256.

Since all probabilities should add up to 1, we can find the missing probability by subtracting the sum of the given probabilities from 1:

1 - 0.256 = 0.744

Therefore, assuming the table represents all possible outcomes, P(X = 9) would be 0.744.

This problem has been solved

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