Find three consecutive odd integers such that the first integer times thesecond integer is one less than four times the third
Question
Solution 1
Let's denote the three consecutive odd integers as x, x+2, and x+4.
According to the problem, the first integer times the second integer is one less than four times the third. This can be written as:
x*(x+2) = 4*(x+4) - 1
Expanding and simplifying the equation gives:
x^2 + 2x = 4x + 16 - 1
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