How many tiles, each 4 decimetre square, will be required to cover the floor of a room 8 m long and 6m broad ?Select one:a. 200b. 260c. 280d. 300
Question
How many tiles, each 4 decimetre square, will be required to cover the floor of a room 8 m long and 6 m broad ?
Select one:
- a. 200
- b. 260
- c. 280
- d. 300
Solution
First, we need to convert the dimensions of the room from meters to decimeters because the size of the tiles is given in decimeters.
1 meter = 10 decimeters
So, the room is 80 decimeters long (8m * 10) and 60 decimeters wide (6m * 10).
The area of the room is length * width = 80 decimeters * 60 decimeters = 4800 decimeter square.
Each tile is 4 decimeter square.
So, the number of tiles required is the area of the room divided by the area of each tile = 4800 decimeter square / 4 decimeter square = 1200 tiles.
However, none of the options (a. 200, b. 260, c. 280, d. 300) match this answer. There might be a mistake in the question or the options provided.
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