The area of four walls of a room is 1440 sq. m. The length is twice its breadth and its heightis 6 m. Find the length and breadth of the room.
Question
Problem Statement
The area of four walls of a room is 1440 sq. m. The length is twice its breadth and its height is 6 m.
Find the length and breadth of the room.
Solution
To solve this problem, we need to use the formula for the area of the four walls of a room, which is 2*(length + breadth)*height.
Given: Area = 1440 sq.m Height = 6 m
We can substitute these values into the formula:
1440 = 2*(length + breadth)*6
Solving this equation gives:
length + breadth = 1440 / (2*6) length + breadth = 120
We also know that the length is twice the breadth. We can represent this as:
length = 2*breadth
Substituting this into the previous equation gives:
2breadth + breadth = 120 3breadth = 120
Solving for breadth gives:
breadth = 120 / 3 breadth = 40 m
Substituting breadth = 40 into the equation length = 2*breadth gives:
length = 2*40 length = 80 m
So, the length of the room is 80 m and the breadth of the room is 40 m.
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