Sure, but you haven't provided the equation of the curve that needs to be rotated about the x-axis. The general formula for the surface area of a curve y = f(x), a ≤ x ≤ b, rotated about the x-axis is given by:

A = 2π ∫ from a to b [f(x) * sqrt(1 + (f'(x))^2)] dx

Where:
- A is the surface area
- f(x) is the function
- f'(x) is the derivative of the function
- a and b are the limits of the integral, representing the interval on the x-axis over which the function is defined and rotated.

Please provide the specific function and the interval [a, b] so I can help you calculate the exact area.

Question

Sure, but you haven't provided the equation of the curve that needs to be rotated about the x-axis. The general formula for the surface area of a curve y = f(x), a ≤ x ≤ b, rotated about the x-axis is given by:

A = 2π ∫ from a to b [f(x) * sqrt(1 + (f'(x))^2)] dx

Where:
- A is the surface area
- f(x) is the function
- f'(x) is the derivative of the function
- a and b are the limits of the integral, representing the interval on the x-axis over which the function is defined and rotated.

Please provide the specific function and the interval [a, b] so I can help you calculate the exact area.

Knowee AI · Accepted Answer

Sure, but you haven't provided the equation of the curve that needs to be rotated about the x-axis. The general formula for the surface area of a curve y = f(x), a ≤ x ≤ b, rotated about the x-axis is given by:

A = 2π ∫ from a to b [f(x) * sqrt(1 + (f'(x))^2)] dx

Where:
- A is the surface area
- f(x) is the function
- f'(x) is the derivative of the function
- a and b are the limits of the integral, representing the interval on the x-axis over which the function is defined and rotated.

Please provide the specific function and the interval [a, b] so I can help you calculate the exact area.

Find the exact area of the surface obtained by rotating the curve about the x-axis.

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