The electric potential at a point due to a charge is expressed mathematically as*1 pointV= kqQ/rV = kQ/rV = kQ/r^2V = kQ/2r
Question
The electric potential at a point due to a charge is expressed mathematically as
1 point
- V = kqQ/r
- V = kQ/r
- V = kQ/r^2
- V = kQ/2r
Solution
The electric potential (V) at a point due to a charge (Q) is given by the formula:
V = kQ/r
where:
- V is the electric potential,
- k is Coulomb's constant (approximately 8.99 x 10^9 N m^2/C^2),
- Q is the charge causing the electric field,
- r is the distance from the point to the charge.
This formula tells us that the electric potential is directly proportional to the charge and inversely proportional to the distance from the charge.
The other formulas you mentioned are not correct for the electric potential due to a point charge.
V = kqQ/r is incorrect because there is only one charge Q involved in the definition of electric potential.
V = kQ/r^2 is the formula for electric field, not electric potential.
V = kQ/2r does not correspond to any known physical quantity in electrostatics.
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