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Express the logarithm ln(9)=2.19722 (to 5 decimal places) in its exponential form

Question

Express the logarithm ln(9)=2.19722 \ln(9) = 2.19722 (to 5 decimal places) in its exponential form

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Solution

1. Break Down the Problem

To express the logarithmic equation ln(9)=2.19722 \ln(9) = 2.19722 in exponential form, we need to understand the relationship between logarithms and exponents. The general form is: ln(a)=b    a=eb \ln(a) = b \implies a = e^b where e e is the base of natural logarithms (approximately 2.71828).

2. Relevant Concepts

Here, we can use the property of logarithms that states: ln(a)=b    a=eb \ln(a) = b \implies a = e^b

3. Analysis and Detail

In our case, setting a=9 a = 9 and b=2.19722 b = 2.19722 , we can rewrite the equation in exponential form.

4. Verify and Summarize

By applying the formula: 9=e2.19722 9 = e^{2.19722} This shows that the exponential form of ln(9)=2.19722 \ln(9) = 2.19722 is indeed 9=e2.19722 9 = e^{2.19722} .

Final Answer

Thus, the exponential form of ln(9)=2.19722 \ln(9) = 2.19722 is: 9=e2.19722 9 = e^{2.19722}

This problem has been solved

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