Calculate the change in entropy associated with freezing of 0.072 mol of C2 H 5 OHat 158.7 K given that the enthalpy of freezing is 4.60 kJ mol-1 .
Question
Calculate the change in entropy associated with freezing of 0.072 mol of C2 H5 OH at 158.7 K given that the enthalpy of freezing is 4.60 kJ mol-1.
Solution
To calculate the change in entropy (ΔS), we can use the formula:
ΔS = ΔH/T
where ΔH is the change in enthalpy and T is the absolute temperature.
Given in the problem, we have:
ΔH = 4.60 kJ/mol = 4600 J/mol (since 1 kJ = 1000 J) T = 158.7 K
Substituting these values into the formula, we get:
ΔS = 4600 J/mol / 158.7 K = 28.97 J/mol·K
So, the change in entropy associated with the freezing of 0.072 mol of C2H5OH at 158.7 K is 28.97 J/mol·K.
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