If a 10C charge is placed in a medium having relative permittivity 5.4, what will be the amount of flux coming out of that charge?

The amount of electric flux (Φ) coming out of a charge is given by Gauss's Law, which states that the total electric flux out of a closed surface is equal to 1/ε times the total charge enclosed by the surface.

The formula is:

Φ = Q / ε

Where: Q = total charge (in this case, 10C) ε = permittivity of the medium

The permittivity of the medium (ε) is the product of the permittivity of free space (ε0) and the relative permittivity (εr).

ε = ε0 * εr

The permittivity of free space (ε0) is a constant and is approximately 8.85 x 10^-12 C^2/N*m^2.

Given that the relative permittivity (εr) is 5.4, we can calculate ε as follows:

ε = ε0 * εr ε = 8.85 x 10^-12 C^2/Nm^2 * 5.4 ε = 47.79 x 10^-12 C^2/Nm^2

Now we can calculate the electric flux (Φ):

Φ = Q / ε Φ = 10C / 47.79 x 10^-12 C^2/Nm^2 Φ = 2.09 x 10^11 Nm^2/C

So, the amount of flux coming out of the 10C charge placed in a medium having relative permittivity 5.4 is 2.09 x 10^11 N*m^2/C.