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Find the product of these complex numbers.(9 + 6i)(7 + 4i) =A.63 + 24iB.63 - 24iC.39 + 78iD.87 + 78iSUBMITarrow_backPREVIOUS

Question

Find the product of these complex numbers.

(9+6i)(7+4i)=A.63+24iB.6324iC.39+78iD.87+78i(9 + 6i)(7 + 4i) = A. 63 + 24i B. 63 - 24i C. 39 + 78i D. 87 + 78i

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Solution

To find the product of two complex numbers, we use the distributive property, also known as the FOIL method in this case. FOIL stands for First, Outer, Inner, Last.

First, we multiply the first terms in each binomial: (9)(7) = 63

Next, we multiply the outer terms: (9)(4i) = 36i

Then, we multiply the inner terms: (6i)(7) = 42i

Finally, we multiply the last terms: (6i)(4i) = 24i^2

Adding these together gives: 63 + 36i + 42i + 24i^2

Remembering that i^2 = -1, we can simplify to: 63 + 78i - 24

Which simplifies to: 39 + 78i

So, the product of (9 + 6i)(7 + 4i) is 39 + 78i. Therefore, the answer is C.39 + 78i.

This problem has been solved

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