In △ABC shown below,  𝑆𝑖𝑛𝐶=45 and the length of AB is 10 inches. What is the length, in inches, of   𝐴𝐶― ?

The question seems to be missing the diagram of triangle ABC. However, based on the given information, we can assume that angle C is opposite side AC.

In a right triangle, the sine of an angle is defined as the length of the opposite side divided by the length of the hypotenuse.

So, if SinC = 45, then we have:

SinC = AC/AB

Rearranging the equation to solve for AC gives:

AC = AB * SinC

Substituting the given values:

AC = 10 * Sin45

The Sin45 is approximately 0.7071 (in most cases you can use this approximation).

So,

AC = 10 * 0.7071 = 7.071 inches

Therefore, the length of AC is approximately 7.071 inches.