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n element with (Z=69) emits 2α and 1β particles in succession. What will be the group number of new element formed?Group 2Group 13Group 5Group 3

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Solution

The atomic number (Z) of an element determines its position in the periodic table and hence its group number.

  1. The atomic number of the given element is 69.

  2. When an element emits an alpha particle, its atomic number decreases by 2. Since the element emits 2 alpha particles, the atomic number decreases by 4 (2*2).

  3. When an element emits a beta particle, its atomic number increases by 1.

  4. Therefore, after the emission of 2 alpha particles and 1 beta particle, the atomic number of the new element will be 69 - 4 + 1 = 66.

  5. The element with atomic number 66 is Dysprosium (Dy), which belongs to the Lanthanide series. The Lanthanides are typically considered part of Group 3 in the periodic table.

So, the new element will belong to Group 3.

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