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If two vriables a and b are related by c= ab then GM.of c =(a) GM of a +GM of b(b) GM of a×GM of b(c) GM of a -GM of b(d) GM of a /GM of b

Question

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Solution

To determine how the geometric mean (GM) of c c relates to the geometric means of a a and b b given the relationship c=ab c = ab , let’s break down the problem and analyze the options.

1. Break Down the Problem

  • We have c=ab c = ab .
  • We want to find out how GM(c) \text{GM}(c) relates to GM(a) \text{GM}(a) and GM(b) \text{GM}(b) .

2. Relevant Concepts

  • The geometric mean of a set of numbers x1,x2,,xn x_1, x_2, \ldots, x_n is given by: GM(x1,x2,,xn)=(x1x2xn)1/n \text{GM}(x_1, x_2, \ldots, x_n) = (x_1 x_2 \cdots x_n)^{1/n}

  • Specifically, for two variables a a and b b , the geometric mean is: GM(a,b)=(ab)1/2 \text{GM}(a, b) = (ab)^{1/2}

3. Analysis and Detail

  • Using the definition, we calculate: GM(c)=GM(ab)=(ab)1/2 \text{GM}(c) = \text{GM}(ab) = (ab)^{1/2}

  • Now, calculate GM(a) \text{GM}(a) , GM(b) \text{GM}(b) : GM(a)=(a)1/1=a \text{GM}(a) = (a)^{1/1} = a GM(b)=(b)1/1=b \text{GM}(b) = (b)^{1/1} = b

4. Relation between GM of c, a, and b

  • Now we need to express this in terms of GM(a) \text{GM}(a) and GM(b) \text{GM}(b) : GM(c)=ab=GM(a)GM(b) \text{GM}(c) = \sqrt{ab} = \sqrt{\text{GM}(a) \cdot \text{GM}(b)}

This suggests that GM(c) \text{GM}(c) is not straightforwardly expressed by any of the linear combinations indicated in the options.

Final Answer

The formulation relates to GM(a) \text{GM}(a) and GM(b) \text{GM}(b) as: GM(c)=(a)(b)=GM(a)×GM(b) \text{GM}(c) = \sqrt{(a)(b)} = \sqrt{\text{GM}(a) \times \text{GM}(b)} Thus, the correct option is:

  • (b) GM of a × GM of b

Therefore, the correct answer is (b)GM(a)×GM(b)(b) \text{GM}(a) \times \text{GM}(b).

This problem has been solved

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