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so we have f(3) = and f '(3) = . Putting these values into this equation, we see that the linearization isL(x)= f(3) + f '(3)(x − 3) = + (x − 3)= .

Question

so we have

f(3) =
and f '(3) = .

Putting these values into this equation, we see that the linearization is
L(x) = f(3) + f '(3)(x − 3) = + (x − 3) = .

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Solution

It seems like you've missed providing the values for f(3) and f'(3). The linearization formula you've provided is correct. It's used to approximate the value of a function near a point (in this case, x=3) using the value of the function at that point and the function's derivative at that point.

The formula is L(x) = f(a) + f'(a)(x - a), where a is the point near which we want to approximate the function. In your case, a = 3.

So, if you provide the values for f(3) and f'(3), I can help you complete the linearization.

This problem has been solved

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