Three terms are in arithmetic progression such that their sum is 36 and product is 1296. Find the three terms.a.4, 12, 20b.9, 12, 15c.8, 12, 16d.6, 12, 18
Question
Solution 1
The three terms in an arithmetic progression can be represented as (a-d), a, (a+d), where a is the middle term and d is the common difference.
Given that the sum of the three terms is 36, we can write the equation:
(a-d) + a + (a+d) = 36 3a = 36 a = 36/3 a = 12
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