What is the output of the following code?#include <stdio.h>int main() { int arr[2][2] = {{1, 2}, {3, 4}}; printf("%d\n", arr[0][2]); return 0;}
Question
What is the output of the following code?
#include <stdio.h>
int main() {
int arr[2][2] = {{1, 2}, {3, 4}};
printf("%d\n", arr[0][2]);
return 0;
}
Solution
The code will result in undefined behavior.
In C, arrays are 0-indexed, which means the first element is at position 0. The array arr is a 2x2 array, so it has elements at positions [0][0], [0][1], [1][0], and [1][1].
However, the code is trying to access the element at position [0][2], which does not exist in the array. This will lead to undefined behavior, as it's accessing memory that is out of the bounds of the array.
So, we can't predict the output of this code. It might crash, or it might print some random value that happens to be in the memory location it's accessing.
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