What is the gross number of ATP molecules produced in Glycolysis disregarding input in one glucose of molecule?Group of answer choices1264

The process of glycolysis converts one molecule of glucose into two molecules of pyruvate, and in this process, it produces a net gain of ATP molecules. To analyze the ATP production in glycolysis, it's important to break down the steps and relevant concepts.

1. ### Break Down the Problem

• Step 1: Understand glycolysis and its stages.
• Step 2: Identify the ATP yield; calculate the gross ATP produced.
• Step 3: Consider the total ATP generated compared to the net gain.

2. ### Relevant Concepts

• ATP Investment Phase: The first five steps consume 2 ATP molecules.
• ATP Payoff Phase: The last five steps produce 4 ATP molecules.

3. ### Analysis and Detail

In total:

• Glycolysis starts with glucose and ends with two pyruvate molecules.
• During the conversion, ATP is both consumed and produced:
  • Input: 2 ATP (used in steps 1 and 3),
  • Output: 4 ATP (produced in steps 7 and 10).

The gross ATP production can be calculated as follows: $\text{Gross ATP produced} = 4 \text{ (output)} - 0 \text{ (since there is no net other than glycolysis)}$ However, the term "gross" typically refers to the total produced without subtracting the initial investment, giving us: $\text{Gross ATP} = 4 \text{ ATP produced} + 2 \text{ ATP consumed} = 6 \text{ ATP}$

4. ### Verify and Summarize

Thus the true gross yield of ATP in glycolysis before accounting for the cost incurred is indeed: 6 ATP molecules produced from one glucose molecule during glycolysis.

Final Answer

The gross number of ATP molecules produced in glycolysis is 6 ATP.