When a sinusoidal voltage E = 200 sin 314 t is applied to a resistor of 10 Ω resistance, the current flowing through the resistor can be calculated using Ohm's law, which states that the current I through a conductor between two points is directly proportional to the voltage V across the two points, and inversely proportional to the resistance R between them. This is mathematically represented as I = V/R.

In this case, the peak voltage V is 200V, the resistance R is 10 Ω, and the current I is what we're trying to find.

Step 1: Identify the peak voltage (V) and resistance (R). In this case, V = 200V and R = 10 Ω.

Step 2: Use Ohm's law to calculate the current. I = V/R = 200V / 10 Ω = 20A.

Therefore, the peak current that flows through the resistor is 20A.

However, since the voltage is sinusoidal, the current will also be sinusoidal. So the current at any time t can be represented as I = 20 sin 314 t.

Question

When a sinusoidal voltage E = 200 sin 314 t is applied to a resistor of 10 Ω resistance, the current flowing through the resistor can be calculated using Ohm's law, which states that the current I through a conductor between two points is directly proportional to the voltage V across the two points, and inversely proportional to the resistance R between them. This is mathematically represented as I = V/R.

In this case, the peak voltage V is 200V, the resistance R is 10 Ω, and the current I is what we're trying to find.

Step 1: Identify the peak voltage (V) and resistance (R). In this case, V = 200V and R = 10 Ω.

Step 2: Use Ohm's law to calculate the current. I = V/R = 200V / 10 Ω = 20A.

Therefore, the peak current that flows through the resistor is 20A.

However, since the voltage is sinusoidal, the current will also be sinusoidal. So the current at any time t can be represented as I = 20 sin 314 t.

Knowee AI · Accepted Answer

When a sinusoidal voltage E = 200 sin 314 t is applied to a resistor of 10 Ω resistance, the current flowing through the resistor can be calculated using Ohm's law, which states that the current I through a conductor between two points is directly proportional to the voltage V across the two points, and inversely proportional to the resistance R between them. This is mathematically represented as I = V/R.

In this case, the peak voltage V is 200V, the resistance R is 10 Ω, and the current I is what we're trying to find.

Step 1: Identify the peak voltage (V) and resistance (R). In this case, V = 200V and R = 10 Ω.

Step 2: Use Ohm's law to calculate the current. I = V/R = 200V / 10 Ω = 20A.

Therefore, the peak current that flows through the resistor is 20A.

However, since the voltage is sinusoidal, the current will also be sinusoidal. So the current at any time t can be represented as I = 20 sin 314 t.

When a sinusoidal voltage E = 200 sin 314 t is applied to a resistor of 10 Ω resistanc

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When a sinusoidal voltage $E = 200 \sin(314 t)$ is applied to a resistor of 10 Ω resistance

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