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The voltage across the ends of a resistor is wtVv sin0= . The r.m.s.value of this voltage is :

Question

The voltage across the ends of a resistor is given by:

wtVv sin(0).

The r.m.s. value of this voltage is :

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Solution

To find the root mean square (r.m.s) value of the voltage expressed as Vv(t)=Vmsin(ωt) V_v(t) = V_m \sin(\omega t) , where Vm V_m is the maximum voltage (amplitude), we will follow the steps below.

1. ### Break Down the Problem

We need to derive the r.m.s. value of a sinusoidal voltage function:

  • Identify the maximum voltage Vm V_m .
  • Apply the formula for r.m.s. value for sinusoidal waves.

2. ### Relevant Concepts

The r.m.s value of a sinusoidal current or voltage is given by the formula:

Vr.m.s=Vm2 V_{r.m.s} = \frac{V_m}{\sqrt{2}}

3. ### Analysis and Detail

  1. Given:
    • The sinusoidal voltage is Vv(t)=Vmsin(ωt) V_v(t) = V_m \sin(\omega t) .
  2. The r.m.s value is calculated as follows:
    • Substitute Vm V_m into the formula: Vr.m.s=Vm2 V_{r.m.s} = \frac{V_m}{\sqrt{2}}

4. ### Verify and Summarize

The formula for r.m.s voltage derived from the definition is consistent and widely used for sinusoidal functions. Thus the calculation is verified as correct.

Final Answer

The r.m.s. value of the voltage across the resistor is:

Vr.m.s=Vm2 V_{r.m.s} = \frac{V_m}{\sqrt{2}}

This problem has been solved

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