From the oblique triangle in which a = 6 cm, b= 9 cm and C = 32 degrees, solve for the angle A.
Question
From the oblique triangle in which
a = 6 cm, b = 9 cm and C = 32 degrees, solve for the angle A.
Solution
To solve for angle A in the oblique triangle, we can use the Law of Sines. The Law of Sines states that the ratio of the length of a side of a triangle to the sine of the angle opposite that side is the same for all three sides of the triangle.
Here's the step-by-step solution:
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Write down the Law of Sines formula: a/sinA = b/sinB = c/sinC
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Substitute the given values into the formula. We know a = 6 cm, b = 9 cm, and C = 32 degrees. We're solving for A, so we'll use the formula a/sinA = b/sinC:
6/sinA = 9/sin32
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Solve for sinA:
sinA = 6*sin32/9
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Calculate the value of sinA using a calculator. Make sure your calculator is set to degrees, not radians.
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Once you have the value of sinA, find the angle A by taking the inverse sine (also known as arcsin or sin^-1) of the value you calculated. This will give you the measure of angle A in degrees.
Remember, the Law of Sines can give an ambiguous case (two possible solutions for a triangle), but in this case, since the given angle C is acute and side a is shorter than side b, there is only one possible solution.
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