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If the random variable X assumes the values 0 and 1 only and is such that P(X = 0) = 3P(X = 1), then the value of E(X) isans.

Question

If the random variable X assumes the values 0 and 1 only and is such that P(X = 0) = 3P(X = 1), then the value of E(X) is ans.

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Solution

The expected value E(X) of a random variable X is calculated as the sum of all possible values of X multiplied by their respective probabilities.

Given that X can take on the values 0 and 1, and that P(X = 0) = 3P(X = 1), we can set up the following equations:

Let P(X = 1) = p, then P(X = 0) = 3p.

Since the sum of all probabilities must equal 1, we have:

p + 3p = 1 4p = 1 p = 1/4

Therefore, P(X = 0) = 3/4 and P(X = 1) = 1/4.

Now, we can calculate E(X):

E(X) = (0 * P(X = 0)) + (1 * P(X = 1)) = (0 * 3/4) + (1 * 1/4) = 0 + 1/4 = 1/4

So, the expected value E(X) is 1/4.

This problem has been solved

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