Knowee
Questions
Features
Study Tools

For the reaction A → B, ΔH = -13 kJ mol-1 and Ea = 31 kJ mol-1 . What is theactivation energy for the reverse reaction B → A?

Question

For the reaction A → B, ΔH = -13 kJ mol-1 and Ea = 31 kJ mol-1 . What is the activation energy for the reverse reaction B → A?

🧐 Not the exact question you are looking for?Go ask a question

Solution

The activation energy for the reverse reaction B → A can be calculated using the formula:

Ea(reverse) = ΔH + Ea(forward)

Where: Ea(reverse) is the activation energy for the reverse reaction, ΔH is the change in enthalpy for the forward reaction, and Ea(forward) is the activation energy for the forward reaction.

Given that ΔH = -13 kJ mol-1 and Ea(forward) = 31 kJ mol-1, we can substitute these values into the formula:

Ea(reverse) = -13 kJ mol-1 + 31 kJ mol-1 = 18 kJ mol-1

So, the activation energy for the reverse reaction B → A is 18 kJ mol-1.

This problem has been solved

Similar Questions

An endothermic reaction, A→ B has an activation energy 15 kcal/mol and energy of the reaction is 5 kcal/mol. The activation energy of the reaction, B → A is:

The activation energy for the forward reaction X Y is 60 KJ mol−1 and ΔH is −20 KJ mol−1. The activation energy for the backward reaction Y X is:

A particular chemical reaction occurs at room temperature (293 K) at half the rate that it does at 300 K. What is the activation energy for this reaction?

If 3 moles of a compound use 12 J of energy in a reaction, what is the Hreaction in kJ/mol?A.-4 kJ/molB.4 kJ/molC.-0.004 kJ/molD.0.004 kJ/mol

At 500K the rate of a bimolecular reaction is ten times the rate at 400K. Find the activation energy of this reaction: a. From Arrhenius’ law.

1/1

Upgrade your grade with Knowee

Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.