If 3 moles of a compound use 12 J of energy in a reaction, what is the Hreaction in kJ/mol?A.-4 kJ/molB.4 kJ/molC.-0.004 kJ/molD.0.004 kJ/mol
Question
If 3 moles of a compound use 12 J of energy in a reaction, what is the Hreaction in kJ/mol?
A. -4 kJ/mol
B. 4 kJ/mol
C. -0.004 kJ/mol
D. 0.004 kJ/mol
Solution
The Hreaction (enthalpy change) is calculated by dividing the energy used by the number of moles. In this case, it would be 12 J divided by 3 moles, which equals 4 J/mol. However, the question asks for the answer in kJ/mol. To convert from J to kJ, you divide by 1000 (since there are 1000 J in a kJ). So, 4 J/mol divided by 1000 equals 0.004 kJ/mol. Therefore, the answer is D. 0.004 kJ/mol.
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