Find the factorization of the polynomial below.121𝑥2−22𝑥+1121x 2 −22x+1A.(22x - 1)2B.(22x + 1)2C.(11x + 1)2D.(11x - 1)2

Question

$121x^2 - 22x + 1$

A. $(22x - 1)^2$
B. $(22x + 1)^2$
C. $(11x + 1)^2$
D. $(11x - 1)^2$

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The given polynomial is 121x^2 - 22x + 1.

We can rewrite this as (11x)^2 - 211x1 + 1^2, which is a perfect square trinomial.

A perfect square trinomial is of the form (a^2 - 2ab + b^2) and can be factored as (a - b)^2.

So, the factorization of the given polynomial is (11x - 1)^2.

Therefore, the correct answer is D. (11x - 1)^2.

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