A pump can fill a tank with water in2 hours. Because of a leak, it took 2 1/3 hours to fill the tank. The leak can drain all the water of the tank in.

The problem is asking for the time it would take for the leak to drain the tank completely.

Step 1: First, we need to determine the rate at which the pump can fill the tank. Since the pump can fill the tank in 2 hours, its rate is 1 tank/2 hours = 0.5 tanks/hour.

Step 2: Next, we need to determine the combined rate of the pump and the leak. Since it took 2 1/3 hours to fill the tank with the leak, the combined rate is 1 tank/(2 1/3 hours) = 1 tank/(7/3 hours) = 3/7 tanks/hour.

Step 3: Now, we can find the rate at which the leak drains the tank. We subtract the combined rate from the rate of the pump: 0.5 tanks/hour - 3/7 tanks/hour = 1/14 tanks/hour. This is the rate at which the leak drains the tank.

Step 4: Finally, we find the time it would take for the leak to drain the tank completely. Since rate = work/time, we can rearrange to find time = work/rate. The work in this case is 1 tank, and the rate is 1/14 tanks/hour. So, time = 1 tank / (1/14 tanks/hour) = 14 hours.

So, the leak can drain all the water of the tank in 14 hours.