Of two numbers, 1/5th of a the greater equal to 1/3rd of the smaller and their sum is 16. Find the numbers.a.7, 5b.9, 7c.11, 5d.10, 6

Let's denote the two numbers as x and y, where x is the greater number and y is the smaller number.

From the problem, we have two equations:

1. 1/5 * x = 1/3 * y (This is because 1/5th of the greater number is equal to 1/3rd of the smaller number)

2. x + y = 16 (This is because the sum of the two numbers is 16)

We can solve these two equations simultaneously to find the values of x and y.

First, let's express y in terms of x using the first equation:

y = 3/5 * x

Now, let's substitute y in the second equation:

x + 3/5 * x = 16

This simplifies to:

8/5 * x = 16

Solving for x gives:

x = 16 * 5/8 = 10

Substituting x = 10 in the equation y = 3/5 * x gives:

y = 3/5 * 10 = 6

So, the two numbers are 10 and 6, which corresponds to option d.