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a chemist performed an experiment to check the percebtage purity of a sample of glucose

Question

A chemist performed an experiment to check the percentage purity of a sample of glucose

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Solution

To determine the percentage purity of a glucose sample, the chemist can follow these general steps:

  1. Break Down the Problem

    • Identify the amount of glucose (pure substance) present in the sample.
    • Determine the total mass of the sample used in the experiment.
  2. Relevant Concepts

    • The formula to calculate percentage purity is given by: Percentage Purity=(mass of pure substancetotal mass of sample)×100% \text{Percentage Purity} = \left( \frac{\text{mass of pure substance}}{\text{total mass of sample}} \right) \times 100\%
  3. Analysis and Detail

    • If the chemist measures the mass of glucose obtained after performing appropriate reactions (e.g., titration), let’s assume it’s mglucose m_{\text{glucose}} .
    • The total mass of the sample before the experiment is denoted as msample m_{\text{sample}} .
    • Substitute values into the percentage purity formula: Percentage Purity=(mglucosemsample)×100% \text{Percentage Purity} = \left( \frac{m_{\text{glucose}}}{m_{\text{sample}}} \right) \times 100\%
  4. Verify and Summarize

    • After calculating the percentage, double-check the values used for mass measurements.
    • Ensure the calculations are correct to derive the final percentage purity.

Final Answer

Once the mass values are substituted into the formula, the final result will yield the percentage purity of the glucose sample. For example, if the mass of pure glucose obtained is 5g and the total mass of the sample is 10g, the calculation would be: Percentage Purity=(5g10g)×100%=50% \text{Percentage Purity} = \left( \frac{5g}{10g} \right) \times 100\% = 50\% Thus, the sample has a percentage purity of 50%.

This problem has been solved

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