If the concentration of glucose  (C6H12O6)  in the blood is 0.9 g L-1, then the molarity of glucose in the blood is 1. 5 M2. 50 M3. 0.005 M4. 0.05 M

To find the molarity of glucose in the blood, we need to convert the concentration from grams per liter (g L-1) to moles per liter (mol L-1).

First, we need to calculate the molar mass of glucose (C6H12O6). The molar mass is the sum of the atomic masses of all the atoms in the molecule.

C6H12O6: (6 * atomic mass of carbon) + (12 * atomic mass of hydrogen) + (6 * atomic mass of oxygen)

Next, we can use the molar mass to convert the concentration from grams to moles.

moles of glucose = concentration of glucose * (1 L / molar mass of glucose)

Finally, we can calculate the molarity by dividing the moles of glucose by the volume in liters.

molarity of glucose = moles of glucose / volume in liters

Let's calculate the molarity using the given concentration of 0.9 g L-1.