X is twice as good a workman as Y and together they finish a piece of work in 18 days. In how manydays will X alone finish the work?26272528

Let's solve this step by step:

Step 1: Let's assume the amount of work to be 1 (for simplicity).

Step 2: Let's denote the work done by X in one day as x and the work done by Y in one day as y.

Step 3: According to the problem, X is twice as good a workman as Y. So, we can write this as x = 2y.

Step 4: Also, together they finish the work in 18 days. So, we can write this as 18(x + y) = 1.

Step 5: Now, we can substitute x from step 3 into step 4 to get 18(2y + y) = 1, which simplifies to 54y = 1.

Step 6: Solving for y, we get y = 1/54.

Step 7: Substituting y back into x = 2y, we get x = 2/54 = 1/27.

Step 8: Therefore, X alone will finish the work in 27 days.