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If A = {1, 2, 3, 4, 5} , B = {a, b, c, d, e} and C = { -, +, x, @, *} , then which of the following is the not the element of set (A x B x C)?

Question

If A = {1, 2, 3, 4, 5} , B = {a, b, c, d, e} and C = { -, +, x, @, *} , then which of the following is the not the element of set (A x B x C)?

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Solution

To solve the problem, we need to determine which option does not belong to the Cartesian product A×B×CA \times B \times C.

1. ### Break Down the Problem

  • Identify the sets:

    • Set A={1,2,3,4,5}A = \{1, 2, 3, 4, 5\}
    • Set B={a,b,c,d,e}B = \{a, b, c, d, e\}
    • Set C={,+,×,@,}C = \{ -, +, \times, @, *\}
  • Understand what the Cartesian product A×B×CA \times B \times C entails:

    • It's the set of all ordered triples (ai,bj,ck)(a_i, b_j, c_k) such that aiAa_i \in A, bjBb_j \in B, and ckCc_k \in C.

2. ### Relevant Concepts

  • The Cartesian product A×B×CA \times B \times C can be calculated as: A×B×C={(x,y,z)xA,yB,zC} A \times B \times C = \{ (x, y, z) \mid x \in A, y \in B, z \in C \}
  • The total number of elements in the Cartesian product is A×B×C |A| \times |B| \times |C| where A=5,B=5,C=5 |A| = 5, |B| = 5, |C| = 5 .

3. ### Analysis and Detail

  • Calculate the number of elements in A×B×CA \times B \times C: A×B×C=5×5×5=125 |A \times B \times C| = 5 \times 5 \times 5 = 125

  • The elements of A×B×CA \times B \times C are structured as:

    • (1,a,),(1,a,+),(1,a,×),(1,a,@),(1,a,),,(5,e,)(1, a, -), (1, a, +), (1, a, \times), (1, a, @), (1, a, *), \ldots, (5, e, *)
  • Since A×B×CA \times B \times C will consist solely of ordered triples formed from AA, BB, and CC, any element not fitting this format cannot belong to A×B×CA \times B \times C.

4. ### Verify and Summarize

If provided with options, we can evaluate each option to see if:

  • It is in the format of (x,y,z)(x, y, z)
  • Each xx is from set AA
  • Each yy is from set BB
  • Each zz is from set CC

Final Answer

The element that does not fit the format of the Cartesian product will be the one that does not have an element from each of sets AA, BB, and CC or does not form a valid ordered triple.

If options are provided, please share them for an accurate identification of the element not in A×B×CA \times B \times C.

This problem has been solved

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