A 5th Order Butterworth LPF having cutoff frequency 1 KHz. What is the approximate level of attenuation at 2 Khz frequency? 3 db 40 dB 30 dB 60 dB
Question
A 5th Order Butterworth LPF having cutoff frequency 1 KHz. What is the approximate level of attenuation at 2 Khz frequency?
- 3 db
- 40 dB
- 30 dB
- 60 dB
Solution
The level of attenuation for a 5th order Butterworth Low Pass Filter (LPF) can be calculated using the formula:
A = 20 * n * log10(f/fc)
where:
- A is the attenuation in dB,
- n is the order of the filter,
- f is the frequency for which we want to find the attenuation,
- fc is the cutoff frequency of the filter.
Given that n = 5, f = 2 kHz, and fc = 1 kHz, we can substitute these values into the formula:
A = 20 * 5 * log10(2/1) = 20 * 5 * 0.301 = 30.1 dB
So, the approximate level of attenuation at 2 kHz frequency is 30 dB.
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