2C4H10+1302 → 8CO2 + 10H2Oassuming oxygen is the limiting reagent, how much butane would remain if 20g grams butane burns in 60 g of oxygen

Question

2C4H10+1302 → 8CO2 + 10H2Oassuming oxygen is the limiting reagent, how much butane would remain if 20g grams butane burns in 60 g of oxygen
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Solution 1

First, we need to determine the molar mass of the reactants and products in the chemical equation.

The molar mass of butane (C4H10) is approximately 58.12 g/mol. The molar mass of oxygen (O2) is approximately 32 g/mol.

Next, we need to convert the given mass of the reactants into moles.

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