What is the energy of a photon that emits a light of frequency 4.47 𝑥x 1014 Hz?A.2.96 𝑥x 10-19 JB.6.71 𝑥x 10-19 JC.1.34 𝑥x 10-19 JD.6.75 𝑥x 10-19 J
Question
What is the energy of a photon that emits a light of frequency 4.47 x 10^14 Hz?
A. 2.96 x 10^-19 J
B. 6.71 x 10^-19 J
C. 1.34 x 10^-19 J
D. 6.75 x 10^-19 J
Solution
The energy of a photon can be calculated using the formula:
E = h * v
where: E is the energy of the photon, h is Planck's constant (6.63 x 10^-34 Joule seconds), and v is the frequency of the light.
Given that the frequency v = 4.47 x 10^14 Hz, we can substitute these values into the formula:
E = (6.63 x 10^-34 J*s) * (4.47 x 10^14 Hz)
E = 2.96 x 10^-19 J
So, the energy of the photon that emits a light of frequency 4.47 x 10^14 Hz is 2.96 x 10^-19 J. Therefore, the correct answer is A. 2.96 x 10^-19 J.
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