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What is the sum of the natural numbers from l to 100, which are not divisible by 7 and 11?2946

Question

What is the sum of the natural numbers from l to 100, which are not divisible by 7 and 11?

2946

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Solution

To find the sum of the natural numbers from 11 to 100100 that are not divisible by 77 or 1111, we will follow the outlined steps.

1. Break Down the Problem

We need to:

  1. Calculate the total sum of natural numbers from 11 to 100100.
  2. Calculate the sum of numbers from 11 to 100100 that are divisible by 77.
  3. Calculate the sum of numbers from 11 to 100100 that are divisible by 1111.
  4. Calculate the sum of numbers from 11 to 100100 that are divisible by both 77 and 1111 (i.e., divisible by 7777).
  5. Use the inclusion-exclusion principle to find the sum of numbers from 11 to 100100 that are divisible by 77 or 1111.
  6. Subtract the above sum from the total sum to get the sum of numbers not divisible by 77 or 1111.

2. Relevant Concepts

  • The sum of the first nn natural numbers can be calculated using the formula: Sn=n(n+1)2 S_n = \frac{n(n + 1)}{2}
  • For the sum of multiples of kk up to nn: S=k(m(m+1)2) S = k \cdot \left(\frac{m(m + 1)}{2}\right) where m=nkm = \left\lfloor \frac{n}{k} \right\rfloor.

3. Analysis and Detail

  1. Total Sum from 11 to 100100: S100=100(100+1)2=5050 S_{100} = \frac{100(100 + 1)}{2} = 5050

  2. Sum of numbers divisible by 77:

    • Number of terms: m=1007=14m = \left\lfloor \frac{100}{7} \right\rfloor = 14
    • Sum of multiples of 77: S7=714(14+1)2=714152=7105=735 S_7 = 7 \cdot \frac{14(14 + 1)}{2} = 7 \cdot \frac{14 \cdot 15}{2} = 7 \cdot 105 = 735
  3. Sum of numbers divisible by 1111:

    • Number of terms: m=10011=9m = \left\lfloor \frac{100}{11} \right\rfloor = 9
    • Sum of multiples of 1111: S11=119(9+1)2=119102=1145=495 S_{11} = 11 \cdot \frac{9(9 + 1)}{2} = 11 \cdot \frac{9 \cdot 10}{2} = 11 \cdot 45 = 495
  4. Sum of numbers divisible by 7777 (LCM of 77 and 1111):

    • Number of terms: m=10077=1m = \left\lfloor \frac{100}{77} \right\rfloor = 1
    • Sum of multiples of 7777: S77=771(1+1)2=771=77 S_{77} = 77 \cdot \frac{1(1 + 1)}{2} = 77 \cdot 1 = 77
  5. Using inclusion-exclusion: S711=S7+S11S77=735+49577=1153 S_{7 \cup 11} = S_7 + S_{11} - S_{77} = 735 + 495 - 77 = 1153

  6. Final Calculation: Sum of numbers not divisible by 7 or 11=S100S711=50501153=3897 \text{Sum of numbers not divisible by \(7\) or \(11\)} = S_{100} - S_{7 \cup 11} = 5050 - 1153 = 3897

4. Verify and Summarize

After careful calculations, we find that the sum of natural numbers from 11 to 100100 that are not divisible by 77 and 1111 is 38973897.

Final Answer

The sum of the natural numbers from 11 to 100100 that are not divisible by 77 and 1111 is 3897.

This problem has been solved

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