What is the molarity of 750 mL of NaCl solution that contains 21.04 g of NaCl?The Periodic TableA.4.8 × 10-4 mol/LB.0.028 mol/LC.28 mol/LD.0.48 mol/L

First, we need to calculate the number of moles of NaCl. The molar mass of NaCl (sodium chloride) is approximately 58.44 g/mol.

So, the number of moles of NaCl = mass (g) / molar mass (g/mol) = 21.04 g / 58.44 g/mol = 0.36 mol

Next, we need to convert the volume of the solution from mL to L because molarity is defined as the number of moles of solute per liter of solution.

So, volume in L = volume in mL / 1000 = 750 mL / 1000 = 0.75 L

Finally, we can calculate the molarity (M) of the solution using the formula:

Molarity (M) = moles of solute / volume of solution in L = 0.36 mol / 0.75 L = 0.48 M

So, the molarity of the NaCl solution is 0.48 mol/L. The correct answer is D. 0.48 mol/L.