What is Δn for the reaction below:2H2O(l) ⟶ 2H2(g) + O2(g) Group of answer choices-33-11
Question
What is Δn for the reaction below:
Group of answer choices
- -33
- -11
Solution
Δn for a reaction is calculated as the difference between the number of moles of gaseous products and the number of moles of gaseous reactants.
In the given reaction: 2H2O(l) ⟶ 2H2(g) + O2(g)
The number of moles of gaseous products is 2 (for H2) + 1 (for O2) = 3 moles.
The number of moles of gaseous reactants is 0, because H2O is in the liquid state.
So, Δn = moles of gaseous products - moles of gaseous reactants = 3 - 0 = 3.
Therefore, Δn for the reaction is 3.
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