Knowee
Questions
Features
Study Tools

Cruising at FL390, M 0.84 is found to give a TAS of 499 kt. The ISA deviaon at this level will be:a.-17b.+17c.+19d.-19

Question

Cruising at FL390, M 0.84 is found to give a TAS of 499 kt. The ISA deviation at this level will be:

a. -17
b. +17
c. +19
d. -19

🧐 Not the exact question you are looking for?Go ask a question

Solution

To find the ISA deviation at FL390, we need to calculate the difference between the true airspeed (TAS) and the expected airspeed based on the International Standard Atmosphere (ISA) conditions.

Step 1: Convert the TAS from knots to meters per second (m/s). 499 kt = 257.06 m/s

Step 2: Calculate the expected airspeed based on the ISA conditions. The ISA conditions at FL390 state that the temperature should decrease by 2 degrees Celsius per 1,000 feet. FL390 is approximately 39,000 feet.

Temperature deviation = -2°C/1,000 ft * 39,000 ft = -78°C

The ISA temperature at sea level is 15°C, so the expected temperature at FL390 would be: 15°C - 78°C = -63°C

Using the formula for calculating the speed of sound in air: Speed of sound (m/s) = 20.05 * √(temperature in Kelvin)

Temperature in Kelvin = -63°C + 273.15 = 210.15 K

Speed of sound = 20.05 * √(210.15) = 295.97 m/s

Step 3: Calculate the Mach number (M) using the TAS and speed of sound. Mach number (M) = TAS / Speed of sound M = 257.06 m/s / 295.97 m/s = 0.868

Step 4: Calculate the ISA deviation. ISA deviation = M - 1 ISA deviation = 0.868 - 1 = -0.132

Step 5: Convert the ISA deviation to a percentage. ISA deviation (percentage) = ISA deviation * 100 ISA deviation (percentage) = -0.132 * 100 = -13.2%

Therefore, the ISA deviation at FL390 is approximately -13.2%.

None of the given options (-17, +17, +19, -19) match the calculated ISA deviation.

This problem has been solved

Similar Questions

Cruising at FL390, M 0.84 is found to give a TAS of 499 kt. The ISA deviaon at this level will be:a.-17b.+17c.+19d.-19

On page 13 in your ESRT determine what 1008.0 millibars (mb) would be in inches of mercury (in of HG*).29.7730.45

When working with the UTM coordinate system, we are in zone:Group of answer choices17N17S17E19S

Overtaking and overtaken vehicles are at 70 and 40 kmph respectively. find (i) OSD

Một quần thể có 6160 cá thể, phân bố trong khoảng không gian rộng 560 m2. Mật độ cá thể của quần thể này là 10 cá thể/m2.9 cá thể/m2.11 cá thể/m2.12 cá thể/m2.

1/1

Upgrade your grade with Knowee

Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.