(9y - 1)(6y2 - y - 4)= ___A.3y2 - 35y + 4B.54y3 - 15y2 - 35y + 4C.54y3 + 3y2 - 35y + 4D.54y3 - 35y + 4
Question
(9y - 1)(6y² - y - 4) =
A. 3y² - 35y + 4
B. 54y³ - 15y² - 35y + 4
C. 54y³ + 3y² - 35y + 4
D. 54y³ - 35y + 4
Solution
To find the product of two binomials, we use the distributive property, also known as the FOIL method (First, Outer, Inner, Last).
So, we have (9y - 1)(6y^2 - y - 4).
First, multiply the first terms in each binomial: 9y * 6y^2 = 54y^3.
Next, multiply the outer terms: 9y * -y = -9y^2.
Then, multiply the inner terms: -1 * 6y^2 = -6y^2.
Finally, multiply the last terms: -1 * -4 = 4.
Now, combine like terms: 54y^3 - 9y^2 - 6y^2 + 4 = 54y^3 - 15y^2 + 4.
So, the correct answer is B. 54y^3 - 15y^2 - 35y + 4.
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