car accelerates from 6 ms–1 16 ms–1 in 10 sec. Calculate(a) the acceleration and(b) the distance covered by the car at that time
Question
car accelerates from 6 ms–1 16 ms–1 in 10 sec. Calculate
(a) the acceleration
(b) the distance covered by the car at that time
Solution
(a) Acceleration is defined as the rate of change of velocity per unit of time. It can be calculated using the formula:
a = (v_f - v_i) / t
where: v_f = final velocity v_i = initial velocity t = time
Substituting the given values:
a = (16 ms–1 - 6 ms–1) / 10 s
a = 10 ms–2
So, the acceleration of the car is 10 meters per second squared.
(b) The distance covered by the car can be calculated using the formula:
d = v_i*t + 0.5*a*t^2
Substituting the given values:
d = 6 ms–1 * 10 s + 0.5 * 10 ms–2 * (10 s)^2
d = 60 m + 500 m
d = 560 m
So, the car covered a distance of 560 meters.
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